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Skills Page

Nuclear Equations
By Richard Treulib, Class of 2000

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A nuclear equation shows how a nucleus gains or loses subatomic particles.

Ex. 1:

11H + 94Be ---> 63Li + 42He

Let's take a look at this part: 94Be . The 9 represents the Mass Number, or the atomic weight of the atom. The 4 represents the Atomic Number, or number of protons.

Rule: The sum of the mass numbers of the reactants equals the sum of the mass numbers of the products .

Using this rule, you can figure out any missing particles in the equation.

Ex. 2:

What is the missing particle in this equation?

2713Al + 42He ---> 3015P + ?

To find the answer, you must add the mass and atomic numbers of the reactants. So, 27 + 4 = 31 , and 13 + 2 = 15 . This means that the products must have a total mass number of 31, and a total atomic number of 15. Subtract the known products from the sums of the reactants. So, 31 - 30 = 1 , and 15 - 15 = 0 . So, the missing particle would look like this: 10x . Now, compare that to your list of particles, and this particle matches up with a neutron. So, the final equation would be:

2713Al + 42He ---> 3015P + 10N .

Here's Some Links You Might Like

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abu006.gif (306 bytes)Types of Radioactive Decayabu006.gif (306 bytes)

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Please forward all questions, comments and criticisms to Gregory L. Curran.
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Last Modified February 07, 2008