The total pressure in a
container is the sum of the partial pressures of all the gases in the container.
That may sound like common sense to you, but that is Dalton's Law of partial
pressures. As simple as it may sound, it is one of the most useful of the gas laws
in real life. A common method of gas collection in the laboratory involves
displacing water from a bottle, so that you know when the bottle is full of an invisible
gas. The gas that is left in the bottle will not be pure, it will be a mixture
that contains a certain amount of water vapor. To find the pressure of the dry gas
alone, we need to subtract out the pressure of the water vapor. This is one way that
Dalton's law of partial pressure can be used. In this form, the formula that we use
looks like this:
Pdry gas = Ptotal
- Pwater vapor
Where P = Pressure
In order to solve
the problem in a real-life situation, you need a reference table that shows the pressure
of water vapor at various temperatures. Your textbook probably has such a table, but
for convenience, I have provided one below. There will be a link at the bottom of
the page where you can print a table out to use on exams.
| Table 7-4a Vapor
Pressure of Water |
Temperature
oC |
Pressure
kPa |
|
Temperature
oC |
Pressure
kPa |
|
Temperature
oC |
Pressure
kPa |
| 0 |
0.6 |
20 |
2.3 |
30 |
4.2 |
| 3 |
0.8 |
21 |
2.5 |
32 |
4.8 |
| 5 |
0.9 |
22 |
2.6 |
35 |
5.6 |
| 8 |
1.1 |
23 |
2.8 |
40 |
7.4 |
| 10 |
1.2 |
24 |
3.0 |
50 |
12.3 |
| 12 |
1.4 |
25 |
3.2 |
60 |
19.9 |
| 14 |
1.6 |
26 |
3.4 |
70 |
31.2 |
| 16 |
1.8 |
27 |
3.6 |
80 |
47.3 |
| 18 |
2.1 |
28 |
3.8 |
90 |
70.1 |
| 19 |
2.2 |
29 |
4.0 |
100 |
101.3 |
| |
|
|
Now we will demonstrate how
one problem of this type would be solved.
Example 1. A sample of hydrogen gas is collected
over water at 14.0 oC. The pressure of the resultant mixture is 113.0
kPa. What is the pressure that is exerted by the dry hydrogen alone?
Solving:
Write the formula you will need:
Pdry gas
= Ptotal - Pwater vapor
Look up the vapor pressure of water at 14.0 oC
on table 18-4a: 1.6 kPa
List what is known and unknown:
Pdry gas = ?
Ptotal = 113.0 kPa
Pwater vapor = 1.6 kPa
Substitute and solve:
Pdry gas = Ptotal - Pwater vapor
Pdry gas = 113.0 kPa - 1.6 kPa
Pdry gas = 111.4 kPa
Another way that you will be
will use this gas law is to simply determine the partial pressure of another gas, other
than water vapor, in a mixture. These types of problems are very easy, and it would
be best to look at the formula below:
Ptotal = P1
+ P2 + . . . Pn
Where P1, P2, and Pn
are the partial pressures of the gases involved.
Below is an
example of how this formula would be used:
Example 2. A mixture of oxygen, hydrogen and
nitrogen gases exerts a total pressure of 278 kPa. If the partial pressures of the
oxygen and the hydrogen are 112 kPa and 101 kPa respectively, what would be the partial
pressure exerted by the nitrogen.
Ptotal = P1 + P2
+ . . . Pn
278 kPa = 112 kPa + 101 kPa + Pnitrogen
Pnitrogen = 278 kPa - (112 kPa + 101 kPa)
Pnitrogen = 65 kPa
Now, practice what you have learned with the links below.
Please forward all questions, comments and criticisms to Gregory L. Curran.
© Copyright 2004 Fordham Preparatory School, All Rights Reserved.
Last Modified February 07, 2008 |